Find the inverse of
f
(
x
)
=
−
2
x
+
3
x
−
5
\displaystyle {f{{\left({x}\right)}}}=\frac{{-{2}{x}+{3}}}{{{x}-{5}}}
f
(
x
)
=
x
−
5
−
2
x
+
3
.
f
−
1
(
x
)
=
\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}=
f
−
1
(
x
)
=
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