Does the series
∑
n
=
8
∞
1
n
\displaystyle {\sum_{{{n}={8}}}^{{\infty}}}\ \frac{{1}}{{n}}
n
=
8
∑
∞
n
1
converge or diverge?
diverges
converges
Does the series
∑
n
=
8
∞
(
−
1
)
n
n
\displaystyle {\sum_{{{n}={8}}}^{{\infty}}}\ \frac{{\left(-{1}\right)}^{{n}}}{{n}}
n
=
8
∑
∞
n
(
−
1
)
n
converge or diverge?
converges
diverges
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