Evaluate the following integral:
∫
1
32
x
−
11
5
\displaystyle {\int_{{1}}^{{32}}}{x}^{{-\frac{{11}}{{5}}}}
∫
1
32
x
−
5
11
d
x
\displaystyle {\left.{d}{x}\right.}
d
x
.
∫
1
32
x
−
11
5
\displaystyle {\int_{{1}}^{{32}}}{x}^{{-\frac{{11}}{{5}}}}
∫
1
32
x
−
5
11
d
x
=
\displaystyle {\left.{d}{x}\right.}=
d
x
=
Preview
Question 1
Submit
Try another version of this question
License
[more..]
\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Decimal values are not allowed