Evaluate the telescoping series or enter DNE if it diverges.
∑
n
=
1
∞
3
1
n
−
3
1
n
+
1
=
\displaystyle {\sum_{{{n}={1}}}^{{\infty}}}{3}^{{\frac{{1}}{{{n}}}}}-{3}^{{\frac{{1}}{{{n}+{1}}}}}=
n
=
1
∑
∞
3
n
1
−
3
n
+
1
1
=
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Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172
Enter DNE for Does Not Exist, oo for Infinity