Find the general solution to the differential equation. (Use
C
\displaystyle {C}
C
for the constant.)
y
′
=
ln
(
x
)
+
tan
(
x
)
\displaystyle {y}^{{′}}={\ln{{\left({x}\right)}}}+{\tan{{\left({x}\right)}}}
y
′
=
ln
(
x
)
+
tan
(
x
)
y
=
\displaystyle {y}=
y
=
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