Given the vector u=8,10\displaystyle \vec{{u}}={\left\langle{8},-{10}\right\rangle}, determine the magnitude and angle of the vector (measured counterclockwise from the positive x-axis, 0θ<360\displaystyle {0}^{\circ}\le\theta\lt{360}^{\circ}). Give the exact magnitude and θ\displaystyle \theta  to 3 decimal places.

u\displaystyle {\left|{\left|\vec{{u}}\right|}\right|} =  

θ\displaystyle \theta = degrees