Solve the following equation for
k
\displaystyle {k}
k
8
(
k
+
1
)
−
5
=
3
(
2
k
−
4
)
−
1
\displaystyle {8}{\left({k}+{1}\right)}-{5}={3}{\left({2}{k}-{4}\right)}-{1}
8
(
k
+
1
)
−
5
=
3
(
2
k
−
4
)
−
1
k
\displaystyle {k}
k
=
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