Solve the following equation for
h
\displaystyle {h}
h
1
3
(
6
h
+
3
)
=
7
−
h
\displaystyle \frac{{1}}{{3}}{\left({6}{h}+{3}\right)}={7}-{h}
3
1
(
6
h
+
3
)
=
7
−
h
h
\displaystyle {h}
h
=
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