Let f(x)=(x+5)2\displaystyle {f{{\left({x}\right)}}}={\left({x}+{5}\right)}^{{2}}f(x)=(x+5)2. Find the inverse of f\displaystyle {f}f restricted to [−5,∞)\displaystyle {\left[-{5},\infty\right)}[−5,∞) .
f−1(x)=\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}=f−1(x)= Preview Question 1
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