Let f(x)=(x−2)2\displaystyle {f{{\left({x}\right)}}}={\left({x}-{2}\right)}^{{2}}f(x)=(x−2)2. Find the inverse of f\displaystyle {f}f restricted to [2,∞)\displaystyle {\left[{2},\infty\right)}[2,∞) .
f−1(x)=\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}=f−1(x)= Preview Question 1
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