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Consider the function ` f(x) = 6 -8 x^2 ` on the interval ` [ -1 , 5 ] `. Find the average or mean slope of the function on this interval, i.e.
` \frac ( f(5) - f(-1) )( 5 - (-1) ) = `  

By the Mean Value Theorem, we know there exists a ` c ` in the open interval ` (-1, 5) ` such that ` f'( c) ` is equal to this mean slope. For this problem, there is only one ` c ` that works. Find it.
 

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