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Use Euler's method with step size `0.4` to compute the approximate `y`-values `y(0.4)` and `y(0.8)`, of the solution of the initial-value problem
`y^(′) = -2 -4 x + 2 y`,   `y(0)=2`.

`y(0.4)=`   ,

`y(0.8)=`   .

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