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Use Euler's method with step size `0.3` to compute the approximate `y`-values `y(0.3)` and `y(0.6)`, of the solution of the initial-value problem
`y^(′) = -2 -2 x + 2 y`,   `y(0)=-1`.

`y(0.3)=`   ,

`y(0.6)=`   .

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