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Use linear approximation, i.e. the tangent line, to approximate
3√1.13√1.1 as follows:
Let f(x)=3√xf(x)=3√x. The equation of the tangent line to f(x)f(x) at x=1x=1 can be written in the form y=mx+by=mx+b
where mm is:
and where bb is:
Using this, we find our approximation for 3√1.13√1.1 is
Let f(x)=3√xf(x)=3√x. The equation of the tangent line to f(x)f(x) at x=1x=1 can be written in the form y=mx+by=mx+b
where mm is:
and where bb is:
Using this, we find our approximation for 3√1.13√1.1 is
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