Use the table below to find:

`(f\circg)(0)` =	`(g\circf)(-1)` =
`(f\circf)(12) = `	`(g\circg)(11) = `

x	-6	-1	0	1	5	10	11	12
`f(x)`	5	11	0	12	-6	10	-1	1
`g(x)`	10	5	12	-6	1	11	-1	0