Use the table below to find:

`(f\circg)(-5)` =	`(g\circf)(1)` =
`(f\circf)(15) = `	`(g\circg)(-3) = `

x	-7	-5	-3	1	5	7	11	15
`f(x)`	11	5	7	15	-5	-3	-7	1
`g(x)`	-7	7	11	-5	1	5	15	-3