Use Newton's method to approximate a solution of the equation

`e^(0.7 x^2) + x - 2 = 0`.

Let ` x_0 = 1 ` be the initial approximation, and then calculate `x_1` and `x_2`.

` x_1 =`  

` x_2 =`  

Hint

Box 1: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity

Box 2: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity