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Using the remainder theorem, find the value of `x^3+7 x^2-20 x+13` when `x = 1` is
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Box 1: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
1
The remainder theorem tells us the value of a polynomial when `x = a` is the remainder when the polynomial is divided by `x - a`.
We'll use synthetic division to divide by `(x - 1)`:
The last entry of the row is the remainder, `1`.
So the value of `x^3+7 x^2-20 x+13` when `x = 1` is `1`.
We'll use synthetic division to divide by `(x - 1)`:
| `1` | `1` | `7` | `-20` | `13` |
| `1` | `8` | `-12` | ||
| `1` | `8` | `-12` | `1` |
The last entry of the row is the remainder, `1`.
So the value of `x^3+7 x^2-20 x+13` when `x = 1` is `1`.