Try another version of this question Find `dy/dx` for `y=-19x+15cosx`. `d/dx(-19x+15cosx)=`
Get help: Box 1: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
To find the derivative `dy/dx` of the function `y=-19x+15cosx`, apply the basic rules of differentiation to each term separately. For the linear term `-19 x`, the derivative is simply the coefficient `-19`. For the trigonometric term `15 cos x`, use the derivative of cosine, remembering to include the chain rule for the coefficient `15`.
Be sure your variables match those in the question `-19-15 sin x`