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Find `dy/dx` for `y=-18x+19cosx`.
`d/dx(-18x+19cosx)=`
To find the derivative `dy/dx` of the function `y=-18x+19cosx`, apply the basic rules of differentiation to each term separately. For the linear term `-18 x`, the derivative is simply the coefficient `-18`. For the trigonometric term `19 cos x`, use the derivative of cosine, remembering to include the chain rule for the coefficient `19`.
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Box 1: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
`-18-19 sin x`