Try another version of this question Find `y'` by (a) applying the Product Rule and (b) multiplying the factors to produce a sum of simpler terms to differentiate. `y=(1-x^2)(x^3-6x-3)` (a) Apply the Product Rule. Let `u=1-x^2` and `v=x^3-6x-3`. `d/dx(uv)=(1-x^2)(`
`)+(x^3-6x-3)(`
`)` (b) Multiply the factors of the original expression, `u` and `v`, to produce a sum of simpler terms.
`y=`
(c) Find `y'` `y'=`
Get help: Box 1: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Box 2: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Box 3: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Box 4: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
Be sure your variables match those in the question
Be sure your variables match those in the question
Be sure your variables match those in the question