Enable text based alternatives for graph display and drawing entry

Try another version of this question

Find `y'` by (a) applying the Product Rule and (b) multiplying the factors to produce a sum of simpler terms to differentiate.

`y=(4-x^2)(x^3+4x+3)`

(a) Apply the Product Rule. Let `u=4-x^2` and `v=x^3+4x+3`.

`d/dx(uv)=(4-x^2)(`   `)+(x^3+4x+3)(`   `)`

(b) Multiply the factors of the original expression, `u` and `v`, to produce a sum of simpler terms.

`y=`  

(c) Find `y'`

`y'=`  



Get help:


↑
X
MathQuill
   x  x  √  n√  |   | (   ) π ∞ DNE
   x  √  (   ) π ∞ DNE
( ) ( ] [ ) [ ] —∞ ∞ ∪ DNE
< > ≤ ≥ or All Real Numbers DNE
log logn ln n√  | | e 
sin cos tan arcsin arccos arctan ⟨ ⟩
[more..]