Find `y'` by (a) applying the Product Rule and (b) multiplying the factors to produce a sum of simpler terms to differentiate.

`y=(6-x^2)(x^3+4x-8)`

(a) Apply the Product Rule. Let `u=6-x^2` and `v=x^3+4x-8`.

`d/dx(uv)=(6-x^2)(`   `)+(x^3+4x-8)(`   `)`

(b) Multiply the factors of the original expression, `u` and `v`, to produce a sum of simpler terms.

`y=`  

(c) Find `y'`

`y'=`  

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Box 1: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
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