Try another version of this question If `10-9 x^2 ≤ f(x) ≤ 10 cos x` for all `x`, find `lim_(x to 0) f(x)` using the Squeeze Theorem. `lim_(x to 0) f(x)=`
Get help: Box 1: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Consider the inequalities for `f(x)` given by `10-9 x^2 ≤ f(x) ≤ 10 cos x` as `x` approaches `0`. Apply the Squeeze Theorem which states: `lim_{x to a} g(x) = L = lim_{x to a} h(x)` and `g(x) \leq f(x) \leq h(x)` for all `x` near `a`, then `lim_{x to a} f(x) = L`. Evaluate the bounding functions: `10 - 9 x^2` and `10 cos(x)`, and use their behavior as `x` approaches `0` to find `lim_{x to 0} f(x)`.
Enter DNE for Does Not Exist, oo for Infinity 10