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The partial fraction decomposition of ` \frac(10)((x-1)(x+1))` can be written in the form of ` \frac(f(x))(x-1) +\frac(g(x))(x+1),` where
`f(x)=`   ,
`g(x)=`   .

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   x  x  √  n√  |   | (   ) π ∞ DNE
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