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Find the derivative of `f(x)=` `2sqrt(x)`, then find `f'(16)`.
`f'(x)=`
`f'(16)=`
`f'(x)=`
`f'(16)=`
Get help:
Box 1: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
`1/sqrt(x)`
Box 2: Enter your answer as a reduced fraction (like 5/3, not 10/6) or as an integer (like 4 or -2)
Do not enter mixed numbers
Enter DNE for Does Not Exist, oo for Infinity
`1/4`