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Integrate the given series expansion of `f`  term-by-term from zero to `x`  to obtain the corresponding series expansion for the indefinite integral of `f`.

`f(x) = (-3 x^2)/(1+x^3)^2 = sum_(n=0)^(oo) (-1)^n 3 n x^(3 n - 1)`

`int_0^x f(t) dt = sum_(n=1)^(oo)`