Try another version of this question Box 1: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Solve the initial-value problem for `y` as a function of `x`.
`(36 - x^2)(dy)/(dx) = 1`, `y(0) = 5`
`y =`
Be sure your variables match those in the question `1/6 (ln (abs(x/6+1))-ln (abs(x/6-1)))+5`