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The equation of the hyperbola that has a center at ` (6,1) `,
a focus at ` (11 , 1) `,
and a vertex at ` (9 , 1 ) `, is

` \frac((x-C)^2)(A^2)-\frac((y-D)^2)(B^2)=1 `

where

` A = `

` B = `

` C = `

` D = `

` \frac((x-C)^2)(A^2)-\frac((y-D)^2)(B^2)=1 `

where

` A = `

` B = `

` C = `

` D = `

Get help:

Box 1: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)

Enter DNE for Does Not Exist, oo for Infinity

3

Box 2: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)

Enter DNE for Does Not Exist, oo for Infinity

4

Box 3: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)

Enter DNE for Does Not Exist, oo for Infinity

6

Box 4: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)

Enter DNE for Does Not Exist, oo for Infinity

1