Try another version of this question When demonstrating that `lim_(x to 1)3 x + 2 =5` with `epsilon=0.1`, which of the following `delta`-values suffices? Get help: Box 1: Select all correct answers
Recall that to satisfy the definition of a limit, the chosen `delta` must ensure that for every `x` within `delta` of `1`, the absolute difference between `3 x + 2` and `5` is less than `epsilon`.
`delta = 1/90`
`delta = 1/30`
`delta = 1/900`