Try another version of this question Convert the exponential equations into logarithmic form: (a) `2^5 = 32` is equivalent to `log_2 C=D`. `C=` and `D=` (b) `64 = 4^3` is equivalent to `log_4 E = F`. `E=` and `F=` (c) `10^2 = 100` is equivalent to `log_10 G = H`. `G=` and `H=` (d) `0.0001 = 10^-4` is equivalent to `log_10 J = K`. `J=` and `K=` Get help:
If `2^5 = 32` is equivalent to `log_2 (A) = B` then `A = 32` and `B = 5`. In other words, `A` is the answer and `B` is the exponent. `32`
`5`
`64`
`3`
`100`
`2`
`0.0001`
`-4`