Try another version of this question
Solve the following equation for `y` given the value for `x`.
`3 x + 2 y = -16 text{ when } x = -2`
Answer: `y=`
Now solve the equation for `y`.
`3 x + 2 y = -16 text{ for } y`
Answer: `y=`
You may need to use parentheses around your numerator or denominator, for example `(2-5y)/3` would be entered as (2-5y)/3.
Get help:
Box 1: Enter your answer as a fraction (like 3/5 or 10/4), an integer (like 4 or -2), or exact decimal (like 0.5 or 1.25)
Enter DNE for Does Not Exist, oo for Infinity
-5
Box 2: Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
`(-16 - 3 x)/2`